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Test Missing Error In Shell Script

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Line : [: Missing `]'

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If -s File In Unix

how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Bash if statement [: missing `]' error [duplicate] up vote 3 down vote favorite 2 This question already has an answer [: too many arguments bash here: Brackets in if condition: why am I getting syntax errors without whitespace? 3 answers I am having trouble with bash. I am trying to put a command in an if statement and then compare it to a string. This works perfectly. echo $(ipcs | grep Shared | awk '{print $2}') When I put it in an if statement I get some problems. $ if [ "$(ipcs | grep Shared | awk '{print $2}')" -eq "Shared"]; then echo expression evaluated as true; else echo expression evaluated shell [: !=: unary operator expected as false; fi bash: [: missing `]' expression evaluated as false $ if [ "$(ipcs | grep Shared | awk '{print $2}')" = "Shared"]; then echo expression evaluated as true; else echo expression evaluated as false; fi bash: [: missing `]' expression evaluated as false $ if [ "$(ipcs | grep Shared | awk '{print $2}')" == "Shared"]; then echo expression evaluated as true; else echo expression evaluated as false; fi bash: [: missing `]' expression evaluated as false I tried ==, =, and -eq because I wasn't sure which one to use. bash shell-script test share|improve this question edited Oct 9 '14 at 21:50 Gilles 374k706831129 asked Oct 9 '14 at 10:28 cokedude 89139 marked as duplicate by Gillesbash Users with the bash badge can single-handedly close bash questions as duplicates and reopen them as needed. Oct 9 '14 at 21:50 This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question. For those wondering: these are not multi-line statements! –Anthon Oct 9 '14 at 10:45 If you just want to check whether the string Shared appears in the command output you might want to consider using the exit status of grep directly e.g. ipcs | { if grep -q "Shared"; then echo "true"; else echo "false"; fi } or ipcs | grep -q "Shared" && echo "true" || echo "false" - see unix.stackexchange.com/a/48536/65304 for example –steeldriver Oct 9 '14 at 12:10 add a comment| 1 Answer 1

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] missing Shell Programming and Scripting Thread Tools Search this Thread Display Modes #1 02-11-2010 infernalhell Registered User Join Date: http://unix.stackexchange.com/questions/160180/bash-if-statement-missing-error May 2009 Last Activity: 19 August 2011, 4:21 AM EDT Posts: 21 Thanks: 0 Thanked 0 Times in 0 Posts test: ] missing Code: $HOLIDAY="" if [ $TODAY == Tue && $HOLIDAY <> Mon ] then echo "1" else echo "2" fi Getting an error --test: ] missing...could some one help on this Last edited by Scott; 02-11-2010 at 03:51 AM.. http://www.unix.com/shell-programming-and-scripting/129806-test-missing.html Reason: Please use code tags Remove advertisements Sponsored Links infernalhell View Public Profile Find all posts by infernalhell #2 02-11-2010 Scott Administrator Join Date: Jun 2009 Last Activity: 27 October 2016, 9:17 PM EDT Location: Zürich Posts: 8,598 Thanks: 343 Thanked 1,093 Times in 949 Posts Should be ... Code: if [ "$TODAY" = Tue -a "$HOLIDAY" != Mon ] Please use CODE TAGS when posting code, logfiles, input files, expected output, etc. Thanks. Remove advertisements Sponsored Links Scott View Public Profile Find all posts by Scott #3 02-11-2010 tene Registered User Join Date: May 2008 Last Activity: 23 January 2013, 12:06 AM EST Location: Chennai Posts: 132 Thanks: 0 Thanked 18 Times in 18 Posts Logical operators should be separated in two brackets. Code: if [ "$TODAY" = Tue ] && [ "$HOLIDAY" != Mon ] Remove advertisements Sponsored Links tene View Public Profile Find all posts by tene « Previous Thread | Next Thread » Thread Tools Show Printable Vers

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring http://stackoverflow.com/questions/15849095/bash-shell-script-error-sh-missing developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.3 million programmers, just like you, helping each other. Join them; http://serverfault.com/questions/407367/how-to-avoid-syntax-error-on-missing-command-line-arguments it only takes a minute: Sign up Bash shell script error sh: [: missing `]' up vote 5 down vote favorite 1 Aim: I'm trying to create a useful shortcut for initializing a git repo locally, and simultaneously creating shell script a remote repo origin on bitbucket or github. This function is added to my .bashrc file in my home directory. Here is the bash function (which yields an error): function initg() { # Defaults to bitbucket API local API="https://api.bitbucket.org/1.0/repositories/" local DATA="name=$3&description=$4&is_private=true&scm=git" local REMOTE="ssh://git@bitbucket.org/$2/$3" # Use github if specified if [ "$1" == "gh" ]; then API="https://api.github.com/user/repos" DATA='{"name":"$3", "description": "$4"}' REMOTE="git@github.com:$2/$3" fi if [ -z "$API" ] || [ -z "$DATA" ] || [ -z "$REMOTE" ] || [ -z test missing error "$2" ] then echo "A parameter is missing or incorrect" else curl -X POST -u $2 ${API} -d ${DATA} git init git add . git commit -m "Created repo" git remote add origin $REMOTE git push -u origin master fi } The error: username@COMPUTER-NAME /path/to/local/repo $ initg gh username bash_test desc sh: [: missing `]' sh: [: missing `]' Enter host password for user 'username': My Question: First, where is my error? Secondly, how might I improve the control flow or structure of this script to achieve the stated goals? git bash shell unix bitbucket share|improve this question asked Apr 6 '13 at 9:18 cjross 4211310 3 Try bash -x initg gh username bash_test desc to see which lines trigger the error. And use the [[ ]] syntax instead of [] (as in one of my scripts for instance) –VonC Apr 6 '13 at 9:50 3 The fact that it's saying sh: seems to imply that it's running in either a proper variant of sh, or bash in POSIX compliance mode, which could be exacerbating the issue. In addition, it's a function so while the code above looks ok, you may actually be invoking the wrong function because it's already sourced –Petesh Apr 6 '13 at 10:25 Try putting the above code followed by the command to trigger the function in a separate file, say test.sh and invoke bash -x test.sh. –devn

Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Server Fault Questions Tags Users Badges Unanswered Ask Question _ Server Fault is a question and answer site for system and network administrators. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top How to avoid syntax error on missing command line arguments? up vote 0 down vote favorite How to avoid syntax error on missing command line arguments? Example shell script: var1=$1; var2=$2; echo $var1 echo $var2 var3=`expr $var1 + $var2`; echo $var3 Output : shell>sh shelltest 2 3 2 3 5 Output : shell>sh shelltest expr: syntax error As no arguments are passed, How can I avoid this and pass my own message instead of "expr: syntax error"? shell-scripting share|improve this question asked Jul 13 '12 at 5:21 Ahn 661510 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted You can check missing argument in shell script using $# variable. For Example: #!/bin/bash #The following line will print no of argument provided to script #echo $# USAGE="$0 --arg1 --arg2" if [ "$#" -lt "4" ] then echo -e $USAGE; else var1=$2; var2=$4; echo `expr $var1 + $var2`; fi share|improve this answer edited Jul 13 '12 at 5:53 answered Jul 13 '12 at 5:47 Abhijeet Kasurde 835718 add a comment| up vote 3 down vote I usually use the "Indicate Error if Null or Unset" parameter expansion to ensure that parameters are specified. For example: #!/bin/sh var1="${1:?[Please specify the first number to add.]}" var2="${2:?[Please specify the second number to add.]}" Which then does this: % ./test.sh ./test.sh: 2: ./test.sh: 1: [Please specify the first number to add.] % ./test.sh 1 ./test.sh: 3: ./test.sh: 2: [Please specify the second number to add.] From the manpage: ${parameter:?[word]} Indicate Error if Null or Unset. If parameter is unset or null, the expansion of word (or a message indicating it is unset if word is omitted) is written to standard error and the shell exits with a nonzero exit status. Otherwise, the value of param

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